(7x+3)(2x^2-9x-5)=0

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Solution for (7x+3)(2x^2-9x-5)=0 equation: 


Simplifying
(7x + 3)(2x2 + -9x + -5) = 0

Reorder the terms:
(3 + 7x)(2x2 + -9x + -5) = 0

Reorder the terms:
(3 + 7x)(-5 + -9x + 2x2) = 0

Multiply (3 + 7x) * (-5 + -9x + 2x2)
(3(-5 + -9x + 2x2) + 7x * (-5 + -9x + 2x2)) = 0
((-5 * 3 + -9x * 3 + 2x2 * 3) + 7x * (-5 + -9x + 2x2)) = 0
((-15 + -27x + 6x2) + 7x * (-5 + -9x + 2x2)) = 0
(-15 + -27x + 6x2 + (-5 * 7x + -9x * 7x + 2x2 * 7x)) = 0
(-15 + -27x + 6x2 + (-35x + -63x2 + 14x3)) = 0

Reorder the terms:
(-15 + -27x + -35x + 6x2 + -63x2 + 14x3) = 0

Combine like terms: -27x + -35x = -62x
(-15 + -62x + 6x2 + -63x2 + 14x3) = 0

Combine like terms: 6x2 + -63x2 = -57x2
(-15 + -62x + -57x2 + 14x3) = 0

Solving
-15 + -62x + -57x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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